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Re: Dimension member property in dimension formula

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Hi Silpa,

 

You can try to use something like COUNT(PERIODSTODATE.... Just test and compare report speed.

 

IIF may be not so bad:

 

IIF([TIME].CurrentMember.Properties("MONTHNUM")="1",[ACCOUNT].[INV],IIF([TIME].CurrentMember.Properties("MONTHNUM")="2",[ACCOUNT].[INV]/2,...

 

 

B.R. Vadim


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